(x+6)(x+4)=168^2

Solution for (x+6)(x+4)=168^2 equation:

(x+6)(x+4)=168^2

We move all terms to the left:

(x+6)(x+4)-(168^2)=0

We add all the numbers together, and all the variables

(x+6)(x+4)-28224=0

We multiply parentheses ..

(+x^2+4x+6x+24)-28224=0

We get rid of parentheses

x^2+4x+6x+24-28224=0

We add all the numbers together, and all the variables

x^2+10x-28200=0

a = 1; b = 10; c = -28200;
Δ = b2-4ac
Δ = 102-4·1·(-28200)
Δ = 112900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112900}=\sqrt{100*1129}=\sqrt{100}*\sqrt{1129}=10\sqrt{1129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{1129}}{2*1}=\frac{-10-10\sqrt{1129}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{1129}}{2*1}=\frac{-10+10\sqrt{1129}}{2}
$